Your Time has Finished
Which UCAT Exam
are you sitting?
Loading...
QR Units in the UCAT (Tutoring)
Your Score:
Average Score of All Users:
You performed better than of students
Section Breakdown
| Your Score | Average of all Users | Percentile | |
|---|---|---|---|
| QR Tutorial 4 edition |
QR Tutorial 4 edition
Your score:
Average score:
You performed better than of students
Let’s do the questions from Tutorial 4
| Bristol | ||||||
| Exeter | 81 | Exeter | ||||
| London | 118 | 200 | London | |||
| Manchester | 168 | 244 | 208 | Manchester | ||
| Norwich | 240 | 322 | 118 | 208 | Norwich | |
| Sheffield | 180 | 256 | 167 | 39 | 155 | Sheffield |
| York | 221 | 297 | 209 | 71 | 180 | 57 |
The table shows the distances (in miles) for automobile journeys between major English cities
1 mile = 1.6 kilometres
Explanation
The correct answer is E.
322 – 180 = 142 miles
142 miles x 1.6 km/mile = 227.2 km, i.e. 227 kilometres
| Bristol | ||||||
| Exeter | 81 | Exeter | ||||
| London | 118 | 200 | London | |||
| Manchester | 168 | 244 | 208 | Manchester | ||
| Norwich | 240 | 322 | 118 | 208 | Norwich | |
| Sheffield | 180 | 256 | 167 | 39 | 155 | Sheffield |
| York | 221 | 297 | 209 | 71 | 180 | 57 |
The table shows the distances (in miles) for automobile journeys between major English cities
1 mile = 1.6 kilometres
Explanation
The correct answer is C.
3 hours and 2 minutes = 182 minutes = 182/60 hours
209 miles = 334.4 km
334.4 km / (182/60) h = 110.2 km/h i.e. 110 kilometres per hour
Tue, 10 Aug 2021 08:43:03
Correct answer isn't posted as an option
Wed, 17 Aug 2022 09:51:27
The correct answer isn't posted as an option. The explanation is correct, however.
| Bristol | ||||||
| Exeter | 81 | Exeter | ||||
| London | 118 | 200 | London | |||
| Manchester | 168 | 244 | 208 | Manchester | ||
| Norwich | 240 | 322 | 118 | 208 | Norwich | |
| Sheffield | 180 | 256 | 167 | 39 | 155 | Sheffield |
| York | 221 | 297 | 209 | 71 | 180 | 57 |
The table shows the distances (in miles) for automobile journeys between major English cities
1 mile = 1.6 kilometres
Explanation
The correct answer is B.
155 miles = 248 km = 248,000 metres
248,000 m / (28 m/s) = 8857 seconds = 147.6 minutes
i.e. 2 hours and 28 minutes (to the nearest minute)
| Bristol | ||||||
| Exeter | 81 | Exeter | ||||
| London | 118 | 200 | London | |||
| Manchester | 168 | 244 | 208 | Manchester | ||
| Norwich | 240 | 322 | 118 | 208 | Norwich | |
| Sheffield | 180 | 256 | 167 | 39 | 155 | Sheffield |
| York | 221 | 297 | 209 | 71 | 180 | 57 |
The table shows the distances (in miles) for automobile journeys between major English cities
1 mile = 1.6 kilometres
Explanation
The correct answer is D.
As usual, there are various possible routes to the answer. One is:
96 km/h = 60 mph = 1 mile per minute
5 hours and 10 minutes = 310 minutes, so the return journey must be 310 miles. Hence, a one-way trip is 155 miles, as in D.
Wed, 17 Aug 2022 09:58:46
Question is incomplete.
| City | Highest recorded temperature (°F) | Lowest recorded temperature (°F) |
| Almaty | 88.1 | 17.8 |
| Shymkent | 96.5 | 22.8 |
| Karaganda | 83.0 | 1.3 |
| Astana | 79.4 | -5.2 |
| Pavlodar | 82.4 | -11.1 |
| Aktobe | 86.9 | 2.6 |
The table shows different extremes of temperature as recorded in several cities in Kazakhstan over the same period of time.
To convert from Celsius to Fahrenheit, a temperature value should be multiplied by 1.8, before adding 32.
Explanation
The correct answer is E.
This is a trick question, because the city with the highest recorded temperature will be the same regardless of the temperature scale used – Shymkent.
| City | Highest recorded temperature (°F) | Lowest recorded temperature (°F) |
| Almaty | 88.1 | 17.8 |
| Shymkent | 96.5 | 22.8 |
| Karaganda | 83.0 | 1.3 |
| Astana | 79.4 | -5.2 |
| Pavlodar | 82.4 | -11.1 |
| Aktobe | 86.9 | 2.6 |
The table shows different extremes of temperature as recorded in several cities in Kazakhstan over the same period of time.
To convert from Celsius to Fahrenheit, a temperature value should be multiplied by 1.8, before adding 32.
Explanation
The correct answer is E.
79.4°F = (79.4 – 32) / 1.8 = 26.3°C (3sf)
1.3°F = (1.3 – 32) / 1.8 = -17.1°C (3sf)
Difference = 26.3 – (-17.1) = 43.4°C (3sf)
Tue, 26 Sep 2023 18:16:04
e
| City | Highest recorded temperature (°F) | Lowest recorded temperature (°F) |
| Almaty | 88.1 | 17.8 |
| Shymkent | 96.5 | 22.8 |
| Karaganda | 83.0 | 1.3 |
| Astana | 79.4 | -5.2 |
| Pavlodar | 82.4 | -11.1 |
| Aktobe | 86.9 | 2.6 |
The table shows different extremes of temperature as recorded in several cities in Kazakhstan over the same period of time.
To convert from Celsius to Fahrenheit, a temperature value should be multiplied by 1.8, before adding 32.
Explanation
The correct answer is C.
In the case of Shymkent:
Highest recorded temp. = (96.5 – 32) / 1.8 = 35.8°C
Lowest recorded temp. = (22.8 – 32) / 1.8 = -5.1°C
Difference = 35.8 – (-5.1) = 40.9°C (3sf)
| City | Highest recorded temperature (°F) | Lowest recorded temperature (°F) |
| Almaty | 88.1 | 17.8 |
| Shymkent | 96.5 | 22.8 |
| Karaganda | 83.0 | 1.3 |
| Astana | 79.4 | -5.2 |
| Pavlodar | 82.4 | -11.1 |
| Aktobe | 86.9 | 2.6 |
The table shows different extremes of temperature as recorded in several cities in Kazakhstan over the same period of time.
To convert from Celsius to Fahrenheit, a temperature value should be multiplied by 1.8, before adding 32.
Explanation
The correct answer is E.
It makes sense to convert this figure into Fahrenheit:
(34 x 1.8) + 32 = 93.2°F
This is lower only than the highest recorded temperature in Shymkent, and so it tops five of the six cities in the table.
| Entrant | Entry weight (lb) |
| Mr Newton | 1115 |
| Mr Feinberg | 1287 |
| Mr Chimedes | 1433 |
| Mr Higgs | 1364 |
| Mr Dalton | 1529 |
| Mr Bing | 1098 |
The table lists the masses, in pounds (lb), of a number of entries into a town’s prize pumpkin competition.
1 kilogram (kg) = 2.2 pounds (lb)
1 pound (lb) = 16 ounces (oz)
1 stone (st) = 14 pounds (lb)
Explanation
The correct answer is B.
All we have to do is to divide by 2.2:
1287 lb = 585 kg
| Entrant | Entry weight (lb) |
| Mr Newton | 1115 |
| Mr Feinberg | 1287 |
| Mr Chimedes | 1433 |
| Mr Higgs | 1364 |
| Mr Dalton | 1529 |
| Mr Bing | 1098 |
The table lists the masses, in pounds (lb), of a number of entries into a town’s prize pumpkin competition.
1 kilogram (kg) = 2.2 pounds (lb)
1 pound (lb) = 16 ounces (oz)
1 stone (st) = 14 pounds (lb)
Explanation
The correct answer is D.
The quickest way is to work out the difference in pounds before converting to stone:
1529 – 1115 = 414 lb = 29.6 st, or 30 to the nearest stone
| Entrant | Entry weight (lb) |
| Mr Newton | 1115 |
| Mr Feinberg | 1287 |
| Mr Chimedes | 1433 |
| Mr Higgs | 1364 |
| Mr Dalton | 1529 |
| Mr Bing | 1098 |
The table lists the masses, in pounds (lb), of a number of entries into a town’s prize pumpkin competition.
1 kilogram (kg) = 2.2 pounds (lb)
1 pound (lb) = 16 ounces (oz)
1 stone (st) = 14 pounds (lb)
Explanation
The correct answer is A.
400 g = 0.4 kg = 0.88 lb
0.9 x 1364 lb / 0.88 lb per pie = 1395 pies (A)
Forgetting to factor in the 90% will give D, 1550 pies.
| Entrant | Entry weight (lb) |
| Mr Newton | 1115 |
| Mr Feinberg | 1287 |
| Mr Chimedes | 1433 |
| Mr Higgs | 1364 |
| Mr Dalton | 1529 |
| Mr Bing | 1098 |
The table lists the masses, in pounds (lb), of a number of entries into a town’s prize pumpkin competition.
1 kilogram (kg) = 2.2 pounds (lb)
1 pound (lb) = 16 ounces (oz)
1 stone (st) = 14 pounds (lb)
Explanation
The correct answer is D.
14 stone x 6 = 84 stone = 1176 lb
This is larger than two of the entries, Mr Newton’s and Mr Bing’s.
| ARS | BDT | HRK | DKK | EGP | FJD | |
| Argentine Pesos (ARS) | 2.16 | 0.13 | 0.11 | 0.43 | 0.04 | |
| Bangladeshi Taka (BDT) | 0.39 | 0.07 | 0.06 | 0.19 | 0.02 | |
| Croatian Kuna (HRK) | 5.61 | 12.54 | 0.96 | 2.69 | 0.33 | |
| Danish Krone (DKK) | 5.72 | 12.69 | 0.94 | 2.75 | 0.29 | |
| Egyptian Pounds (EGP) | 2.04 | 4.57 | 0.25 | 0.31 | 0.10 | |
| Fiji Dollars (FJD) | 17.22 | 38.94 | 2.70 | 2.97 | 8.12 |
The table shows the exchange rates for a number of global currencies listed at a travel agents’. One unit of the currency on the left-hand side can be used to buy the given number of units of each currency along the top. For example, 1 Danish Krone can be exchanged for 0.94 Croatian Kuna.
Explanation
The correct answer is A.
2000 ARS x 0.04 FJD/ARS = 80 FJD
80 FJD x 17.22 ARS = 1377.6 ARS
2000 – 1377.6 = 622 pesos, to the nearest whole number.
| ARS | BDT | HRK | DKK | EGP | FJD | |
| Argentine Pesos (ARS) | 2.16 | 0.13 | 0.11 | 0.43 | 0.04 | |
| Bangladeshi Taka (BDT) | 0.39 | 0.07 | 0.06 | 0.19 | 0.02 | |
| Croatian Kuna (HRK) | 5.61 | 12.54 | 0.96 | 2.69 | 0.33 | |
| Danish Krone (DKK) | 5.72 | 12.69 | 0.94 | 2.75 | 0.29 | |
| Egyptian Pounds (EGP) | 2.04 | 4.57 | 0.25 | 0.31 | 0.10 | |
| Fiji Dollars (FJD) | 17.22 | 38.94 | 2.70 | 2.97 | 8.12 |
The table shows the exchange rates for a number of global currencies listed at a travel agents’. One unit of the currency on the left-hand side can be used to buy the given number of units of each currency along the top. For example, 1 Danish Krone can be exchanged for 0.94 Croatian Kuna.
Explanation
The correct answer is D.
5000 EGP x 0.25 HRK/EGP x 0.96 DKK/HRK = 1200 DKK
5000 EGP x 0.31 DKK/EGP = 1550 DKK
1550 – 1200 = 350 DKK
| ARS | BDT | HRK | DKK | EGP | FJD | |
| Argentine Pesos (ARS) | 2.16 | 0.13 | 0.11 | 0.43 | 0.04 | |
| Bangladeshi Taka (BDT) | 0.39 | 0.07 | 0.06 | 0.19 | 0.02 | |
| Croatian Kuna (HRK) | 5.61 | 12.54 | 0.96 | 2.69 | 0.33 | |
| Danish Krone (DKK) | 5.72 | 12.69 | 0.94 | 2.75 | 0.29 | |
| Egyptian Pounds (EGP) | 2.04 | 4.57 | 0.25 | 0.31 | 0.10 | |
| Fiji Dollars (FJD) | 17.22 | 38.94 | 2.70 | 2.97 | 8.12 |
The table shows the exchange rates for a number of global currencies listed at a travel agents’. One unit of the currency on the left-hand side can be used to buy the given number of units of each currency along the top. For example, 1 Danish Krone can be exchanged for 0.94 Croatian Kuna.
Explanation
The correct answer is C.
150 FJD x 38.94 BDT/FJD = 5841 BDT
450 DKK x 12.69 BDT/DKK = 5710.50 BDT
5841 – 5710.50 = 130.50 BDT more for the Fiji Dollars
| ARS | BDT | HRK | DKK | EGP | FJD | |
| Argentine Pesos (ARS) | 2.16 | 0.13 | 0.11 | 0.43 | 0.04 | |
| Bangladeshi Taka (BDT) | 0.39 | 0.07 | 0.06 | 0.19 | 0.02 | |
| Croatian Kuna (HRK) | 5.61 | 12.54 | 0.96 | 2.69 | 0.33 | |
| Danish Krone (DKK) | 5.72 | 12.69 | 0.94 | 2.75 | 0.29 | |
| Egyptian Pounds (EGP) | 2.04 | 4.57 | 0.25 | 0.31 | 0.10 | |
| Fiji Dollars (FJD) | 17.22 | 38.94 | 2.70 | 2.97 | 8.12 |
The table shows the exchange rates for a number of global currencies listed at a travel agents’. One unit of the currency on the left-hand side can be used to buy the given number of units of each currency along the top. For example, 1 Danish Krone can be exchanged for 0.94 Croatian Kuna.
Explanation
The correct answer is E.
175 x (0.43 EGP – 0.19 EGP) = 42 EGP
What is one-twentieth of one-fiftieth of one-hundredth?
Explanation
The correct answer is E.
1/20 x 1/50 x 1/100 = 1/1,000 x 1/100 = 1/100,000
A, B and C are too large, and D is too small
1% = 1/100, so 0.001% = 1/100,000
On the planet Zoog, 1 frump is worth 12 monads. There are 9 toubs to a rolot and 4 rolots in a gnit, and 5 gnits make up a frump – two-and-a-half of which make up a boole.
Explanation
The correct answer is C.
Booles are irrelevant to the question. A frump is worth 5 gnits, and thus 20 rolots or 180 toubs. So, 180 toubs is worth 12 monads, and our answer must be 180/12 = 15
Huud runs in the local cross-country competition at a speed of 4.8 metres per second. Meanwhile, his pet snail, Ewan, spreads slime over a tile on his back patio at a rate of 3 square inches per minute. The race is 9 miles long and the square tile has side length 30 centimetres.
1 inch = 2.5 cm
1 mile = 1.6 km
Explanation
The correct answer is D.
Huud: 9 miles x 1600 = 14000 m, divided by 4.8 m/s = 3000 seconds, divided by 60 seconds/min = 50 minutes
Ewan: 30 cm / 2.5 = 12 inches, 12 x 12 = 144 square inches,
Divided by 3 square inches/second = 48 minutes
Conversion information:
1 kg = 2.2 pounds (lb)
1pound (lb) = 16 ounces (oz)
1 foot = 12 inches
1 inch = 2.5 cm
Explanation
The correct answer is E.
12.8 g = 0.0128 kg, x 2.2 = 0.02816 lb
1 inch3 = 2.53 cm3 = 15.625 cm3
Therefore, the density = 0.02816 lb x 2/15.625 inch3 = 2.2 lb/inch3
QR Tutorial 4 edition Review Screen
Instructions
Below is a summary of your answers. You can review your questions in three (3) different ways.
The buttons in the lower right-hand corner correspond to these choices:
1. Review all of your questions and answers.
2. Review questions that are incomplete.
3. Review questions that are flagged for review. (Click the 'flag' icon to change the flag for review status.)
You may also click on a question number to link directly to its location in the exam.
QR Tutorial 4 edition Section
Final Answer Review Screen
Instructions
This review section allows you to view the answers you made and see whether they were correct or not. Each question accessed from this screen has an 'Explain Answer' button in the top left hand side. By clicking on this you will obtain an explanation as to the correct answer.
At the bottom of this screen you can choose to 'Review All' answers, 'Review Incorrect' answers or 'Review Flagged' answers. Alternatively you can go to specific questions by opening up any of the sub-tests below.
QR Tutorial 4 edition Section
TI-108