Speed as well as accuracy is important in this section. Work quickly, or you might not finish the paper. There are no penalties for incorrect responses, only marks for correct answers, so you should attempt all questions. Each question is worth one mark.

Calculators are NOT permitted.

Here you will find all TSA Ordered questions that have been written 2008-2019.

Peter is having a large conservatory built at the back of his Below is a plan of the project, showing when each part of the conservatory is to be built.

Each blocked square on the plan represents one man for one day.

25. How many days labour will Peter have to pay for, and what is the maximum number of workers on site at the same time?
4
0

## Explanation

To find the maximum number of workers on site at the same time, look at the part of the plan where vertically (in a single column) there appears to be the most shaded blocks. This is on the columns representing both the 12th and the 13th of April, where there are 2 men for brickwork, 1 man for roof and 1 man for glass, so a total of 4 men. So we know our answer must be B or D. To work out how many days labour Peter will have to pay for, count how many shaded blocks there are on the entire plan, which is 58. Therefore the answer is D.

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A netball tournament is divided into two stages. In the first stage, the teams are divided into equal groups within which each team plays every other team once. In the second stage, the winners of each group take part in a knockout competition which starts with four quarter finals.

32. Which of the following could be the number of teams starting the tournament?
1
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## Explanation

At the start of the 4 quarter finals, we would need 8 teams (2 per final), but as these 8 teams are the winners of the previous stage, there must have been 8 groups, so there were more than 8 teams starting, so eliminate A. As there were 8 groups before the quarter finals and each group consisted of the same number of teams, the total number of teams at the start must have been a multiple of 8. Out of the remaining answers B-E, only 72 is a multiple of 8, therefore E is the answer.

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Every year the 12 local teams that compete for the Tipley and District Tiddlywinks Trophy are split into two leagues for the purpose of eliminating four of the teams, and sorting out the pairings for the knockout stage of the competition. The table below shows how this is done (QF is Quarter Final).

 1st QF Winners League A v 4th place League B 2nd QF 3rd place League A v Runners-up League B 3rd QF Winners League B v 4th place League A 4th QF 3rd place League B v Runners-up League A 1st Semi-final Winners of 1st QF v Winners of 2nd QF 2nd Semi-final Winners of 3rd QF v Winners of 4th QF

This year’s league stage has just been completed, with the following results.

 League A League B 1st The Scorpions The Scales 2nd The Fish The Bulls 3rd The Bearers The Goats 4th The Rams The Archers 5th The Crabs The Maidens 6th The Lions The Twins

Despite having finished 3rd in their league, the reigning champions, The Goats are still confident of reaching the final.

43. If The Goats are successful, what are the alternatives as to their prospective opponents in the final?
0
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## Explanation

As a first step we can trace through the matches that The Goats will play on the way to the Finals, as any opponents they defeat during the Quarterfinals or Semi-finals will not make it to the finals and will therefore not be one of the prospective opponents. We can see that they will first play in the 4th QF against the runners-up in League A, which are the The Fish. Hence as they will have to defeat the Fish to get through to the Finals, The Fish are not possible opponents of The Goats in the Finals. We can therefore rule out answer options A and B. The Goats will next play in the 2nd Semi-finals against the winners of the 3rd QF. We can see the two teams playing in the 3rd QF are the Scales and the Rams. One of these teams will fail in the QFs while the other will lose to the Goats in the Semi-finals if the Goats are going to make it to the Finals, hence any answer options including either of these teams can be ruled out. This leaves us with answer options C and E. The only difference between these options is the Archers in C and The Twins in E. A glance at the table shows that the Twins finished last in League B. They therefore do not play in any of the QFs and have no chance of ending up in the final so we can exclude E, giving us the correct answer option of C.

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19. What is the best conclusion?
0
1

## Explanation

The data provided looks at the thoughts of young smokers and parents perceptions of attitudes of eachother around smoking. Answer A is unknown from the information provided, as this is not something asked. Answer C is incorrect. Answer D is not covered in the data. Answer E is subjective and therefore not something that can be concluded from the data provided. Answer B can be concluded as true, and is the only viable answer option.

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This is the draw for this year’s end of season knockout trophy (and the results so far) competed for by sixteen teams that take part in a quiz league:

Although teams are drawn against each other, all participating teams in each round answer the same set of 50 questions, worth 2 points each.

In the first round, each ‘match’ is won straightforwardly by the team with the higher number of points. This team carries half of these points through to the next round; then in subsequent rounds winners carry through half of their ‘new’ points from the previous round. For example, the Amber Aardvarks carried 39 points through to their quarter-final, then in the quarter-final itself they added 86, and so carried 43 through to their semi-final.

43. How many more points (at least) must the Indigo Iguanas score than the Orange Ocelots in the final to win the trophy?
0
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## Explanation

II : 82 115 118

OO: 76 130 128

The Indigo Iguanas carried 82/2 = 41 points to the Quarter-final

They then carried (125 – 41)/2 = 42 points to the semi-final.

They then carried (118 – 42)/2 = 38 points to the final.

The Orange Ocelots carried  76/2 = 38 points to the quarter-final.

They then carried (130 – 38)/2 = 46 points to the semi-final.

They then carried (128 – 46)/2 = 41 points to the final.

41 – 38 = 3 The Indigo Iguanas must score at least 4 more than the Orange Ocelots in order to win in the finals.

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A group of Construction students must choose their specialist options from the following list:

Bricklaying, Damp-proofing, Drainage, Flooring, Joinery, Plastering, Roofing

Each student must choose three options. The available options may be combined with each other in any way, with the exception of the restrictions that Damp-proofing and Drainage together may not be combined with Bricklaying or Plastering because of timetable constraints, and that students choosing Joinery must also choose Flooring.

49. How many possible combinations including Drainage could the students choose from?
0
2

## Explanation

Let bricklaying=B, Damp-proofing=Dp, drainage=D, flooring=F, joinery=J, plastering=P, roofing=R.

Post Comment
U Medicmind Tutor

Mon, 24 Jul 2023 16:12:43

Is there a more clear explanation on the process

anon Medicmind Tutor

Thu, 05 Oct 2023 09:20:43

why is it C?

Kingsbury School Examination Schedule for the first week of June

 Monday Tuesday Wednesday Thursday Friday History 3hrs English Lit 3hrs Maths 2hrs Economics 2hrs Maths 2hrs English Lit 2 hrs Physics 3hrs Latin 2hrs History 2hrs Latin 2hrs OXQFK OXQFK OXQFK OXQFK OXQFK Geography 2hrs 30mins Chemistry 3hrs English Lang 2hrs 30mins Economics 2hrs 30mins – Biology 1hr 30mins French 2hrs Spanish 2hrs German 2hrs –

All exams take place in the school hall. All morning exams start at 9am, all afternoon exams start at 2pm. Each session (morning or afternoon) must have at least one male and one female invigilator. Each examination must be invigilated by one teacher of that subject. Each person can only invigilate once a day.

Of the male teachers, Ian teaches Economics and German, Mike teaches French and German, and Keith teaches French and Spanish. Of the female teachers, Marjorie teaches Maths and English, Susan teaches Spanish and Latin, and Jenny teaches English and History,

7. Who will invigilate on Wednesday afternoon?
0
1

## Explanation

For this question you only need to focus on the exams on Wednesday as there are no roles dictating whether or not invigilators can or cannot work a certain number of days consecutively. Therefore, the data for the other exams is just extra information. First, we can go through the 4 exams taking place that day and ensure that there is one invigilator present that teaches that subject. Only Marjorie teaches maths, and only Susan teaches Latin hence they must both be present during the morning session (meaning that they can therefore no longer invigilate during the afternoon session). The question does note that there must be at least one male and one female invigilator during each session, but since any of the 3 male teachers can fill that role we can move onto the afternoon session. Both Jenny and Marjorie teach English, but since Marjorie has already invigilated for the day, Jenny must be present during the evening session. Similarly, both Susan and Keith teach Spanish, but since Susan already invigilates during the morning session on Wednesday, Keith must be present during the afternoon session. Hence both Keith and Jenny invigilate on Wednesday afternoon and the answer is C.

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A boxed up board game consists of the following components:

1 playing board

50 question cards

6 playing pieces

40 money tokens

12 bonus tokens

2 dice

The producers of the board game have all the component parts manufactured separately and sent to their warehouse, where they box them up and send them to retailers in cartons of 8 complete games. In their warehouse they have: 98 playing boards; 5,000 question cards; 1,000 playing pieces; 5,000 money tokens; 1,000 bonus tokens and 300 dice.

13. What is the maximum number of cartons of eight games they can dispatch from their warehouse?
0
0

## Explanation

We need to find the component that will limit the number of board games we can make. We can do this by dividing the number of that particular item in the warehouse by the number required in one board game. Playing boards=98/1=98, question cards=5000/50=100, playing pieces=we don’t really need to calculate because by inspection we can estimate that the answer will be more than 98, money tokens=we don’t need to calculate because there are the same number in the warehouse as there are question cards but the number needed for one board game is lower so the answer will be higher than for question cards, bonus tokens=1000/12=83(rounded down to the nearest whole number), dice=again we don’t need to calculate because will obviously be larger than 83. The bonus tokens limit the number of board games that can be dispatched, which is 83. But the answer asks how many cartons can be dispatched, which each contain 8 board games. So the final calculation would be 83/8=10(rounded down to the nearest whole number).

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In the elections for the mayor of Bitton, the single transferable vote system is used. In this, each voter places a ‘1’ beside the candidate they most want and a ‘2’ beside their second Voters may only vote for two candidates. In the first round of counting all the ‘1’ votes are counted. If no candidate has over 50% of the votes, the bottom candidate in the poll drops out and the ‘2’ votes of all those who voted for this candidate are added to the appropriate other candidates. This process continues until one candidate has over 50% of the vote – this person is then elected mayor.

The votes after the first round of counting were as follows: Malcolm Green 87

Susan Johnson 63

Pedro Gonzalez 45

Ian McBride        36

Wayne Daniels 18

Reeta Mathur     17

48. How many candidates can still win?
0
4

## Explanation

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Peace Medicmind Tutor

Sat, 15 Oct 2022 08:32:37

Where is the explanation for this question?

Dina Medicmind Tutor

Tue, 01 Nov 2022 13:48:45

No explanation：（

123 Medicmind Tutor

Thu, 17 Aug 2023 16:03:01

Alejandro Vendetta Medicmind Tutor

Wed, 27 Sep 2023 12:36:04

Who writes these solutions? How comes some are missing ?

Not a medic mind tutor lol Medicmind Tutor

Thu, 12 Oct 2023 07:09:04

=D. This is because nobody has a majority at the beginning, so Reeta is eliminated. Even if all of the second votes from Reeta’s voters went to Wayne Daniels he would still have less votes that Ian McBride – therefore Wayne Daniels will be kicked out next. However, if all of Reeta’s and Wayne’s second votes went to Ian McBride then he would have 71 votes, meaning Pedro Gonzalez is kicked out and if all of Pedro’s second votes went to Ian McBride then Ian could win. If Ian can win, then obviously in a different scenario all of those with more votes than him

Not a medic mind tutor lol Medicmind Tutor

Thu, 12 Oct 2023 07:10:24

...Then then obviously in a different scenario all of those with more votes than him could win – so the top 4 could all win, Hence D is the correct answer.

I stopped in a town called Akeland to ask the way to Eksberg. The only sense I could get from a local was as follows:

Akeland is east of Benford.

Eksberg is north of Cranton.

Ducton is south of Akeland.

Cranton is west of Ducton.

8. Assuming that ‘east’ means, as near as it matters, ‘due east’, which one of the following can be said with certainty?
0
0

## Explanation

Draw out what you know, representing each place using the first letter of the name of the place. Taking the statements in order, A is east of B, so write B A. E is north of C but we don’t know either of their positions relative to A or B, so leave E and C for now. D is south of A, so write D below A. C is west of D, so write C to the right of D. Going back to the second statement, E is north of C, so write E above C. We know that C is west of D (which is below A) and that E is above C, therefore E must be west of A. However we do not know whether E is north or south of A, because we don’t know whether C is north or south of A. If C was south of A, E could be north or south of A because E is above C, and if C was north of A, E would also be north of A. Therefore B is the answer.

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Thomas needs to book a place to sit a test next week, but is free only in the mornings. The test centre runs the test every day from Monday to Friday and holds a morning and an afternoon Each sitting has a total of 100 places available and will take place in the main hall unless there are 30 or fewer candidates, in which case a smaller room is used. He does not like to take tests in crowded places, so he wants to make sure that he is in the main hall and will try to be with the smallest number of other candidates possible. The number of places that are still available are shown in the table below.

20. On which day should he choose to sit the test?
0
1

## Explanation

We can ignore all the pm slots as Thomas is only free in the mornings. He wants to be in the main hall, and therefore we can exclude any slots where there are 70 or more available spaces (as this means that there are 30 or fewer candidates). This means that he cannot do Monday. From the remaining days we want to pick the day with the highest number of spaces available so that he is with the smallest number of candidates possible while still being in the main hall. The highest number of available spaces is present on Friday, so the correct answer option is E.

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A popular option at the Pizza Parlour is the ‘Plus Two’ pizza, which is a basic cheese and tomato pizza plus a choice of any two different additional toppings from the following list:

Tuna      Ham      Chicken      Onion      Mushroom      Sweetcorn

This gives 15 variations, which can be calculated as follows:

Each of the six additional toppings can be combined with one of the other five to create 30 pairs, but this counts each pair twice, e.g. tuna and ham; ham and tuna.

26. Which of the following does not give a result of 15?
0
0

## Explanation

Answer A gives 15 because if 6 teams play the other 5 you would do 6×5=30, but this must be halved to give 15 (because team 1 playing team 2 is equivalent to team 2 playing team 1). Answers B, C and D follow the same principle as answer A. But answer E is different because friend 1 sending a card to friend 2 is not equivalent to friend 2 sending a card to friend 1, therefore the calculation would be 6×5=30 but it would not be necessary to divide 30 by 2.

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Graham recorded the number of visitors to his shop each day last week and presented the results in the bar chart below:

When he calculated the number of customers per hour he found that he had the same number for five of the days, but the values for Tuesday and Friday were slightly higher. The opening hours of the shop are as follows:

38. Which one of the following could be the opening hours of the shop for Tuesday and Friday?
1
0

## Explanation

Find a proportion for the number of customers per hour on Monday by dividing the number of divisions equal to the height of the bar on the graph for Monday by the number of hours open on Monday: 4/10=0.4 . If the number of customers per hour was the same on Tuesday as Monday, you could calculate the numbers of hours open by dividing the height of the bar graph for Tuesday by 0.4: 3/0.4, which can be done without a calculator by doing 3 divided by 2/5 which is equivalent to 3 x 5/2 = 15/2=7.5 . But the question states that the number of customers per hour was higher on Tuesday and Friday, so on Tuesday the shop must have been open for less than 7.5 hours, eliminate answers A, B, C and D. This means E must be the answer. This can be checked by using a similar method to calculate how many hours the shop could have been open for on Friday: 4/0.4=10, so the shop was open for less than 10 hours on Friday.

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Elsie has six Their birthdays are as follows:

Remarkably, in non-leap years the boys’ birthdays are on the 50th, 150th, 250th and 350th days of the year, whilst the girls’ birthdays are on the 123rd and 321st days, and all six are on different days of the week.

19. Which other grandchild’s birthday is on the same day of the week as Ryan’s in a leap year?
0
0

## Explanation

For birthdays to be on the same day of the week, the number of days between two birthdays must be a multiple of 7. In a leap year, Ryan’s birthday will still be on the 50th day (as it is before the 29th of February). The rest of the boys’ birthdays would be on the 151st, 251st and 351st days; the girls’ birthdays would be on the 124th and 322nd days. Subtract 50 from each number day to find the difference in number of days: 151-50=101, 251-50=201, 351-50=301, 124-50=74, 322-50=272. The only difference in number of days that is a multiple of 7 is (351-50=)301. This represents Robert’s birthday (as it is the latest in the year out of the boys), so the answer is D.

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A hotel offers its guests a dinner allowance of £28.50 per A guest wishes to spend up to her allowance on a three course meal without overspending.

 STARTER PRICE (£) Soup of the day 5.00 Prawn cocktail 6.50 Smoked salmon 6.10 Duck confit salad 6.95 MAIN COURSE Sirloin steak 8 ozs. 14.90 Gammon steak 12.50 Rainbow trout 16.10 Duck a l’orange 15.15 Vegetarian risotto 12.75 DESSERT Cheese and biscuits 6.10 Cheesecake 5.60 Apple pie and cream 5.30 Lemon sorbet 5.20 Profiteroles 6.20
24. What is the largest sum she can spend without exceeding the limit?
0
0

## Explanation

Start by adding together the most expensive item from each category: 6.95+16.10+6.20=29.25 which exceeds her limit by 0.75. Try to find an item/items you could switch which would be closest to 0.75 as possible. Keep 16.10 for the main meal because the 2nd most expensive option is 0.95 less. The combination which gives the highest total below 28.50 is 6.10+16.10+6.20=28.40.

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Three night security guards, Robert, Sheila and Tom, are assigned to guard a factory for five consecutive nights, Monday night to Friday night inclusive.

Two of the guards are to be on duty each night. Tom must be on duty for four nights and Robert and Sheila are on duty for three nights each. Regulations do not allow any guard to work for more than two consecutive nights.

12. If Robert is on duty on Friday night, then the nights when Sheila is on duty are
1
0

## Explanation

For this question it is easiest if you create a table as shown, of all the days and jot down which guards are working on which nights. We were already told that Robert is working on Friday. The next piece of information that we can fill in is the days that Tom is working because he is working for 4 nights and as he cannot work for more than 2 consecutive nights, this must mean that he works on Monday, Tuesday, Thursday and Friday. As a result, this means that both Robert and Sheila must be working on Wednesday. Since he cannot work for more than 2 consecutive nights, Robert cannot work on Thursday, so it much be Sheila who does her shift that night and as Sheila cannot work more than 2 consecutive nights, Robert would have to work on Tuesday, which means that Sheila works on Monday to complete all three of her shifts. Therefore, the answer is C.

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Bob, Eve, Nan, Pip and Viv took part in a 6-hour sponsored bowling marathon to raise money for charity. They were all sponsored per  complete 100 points scored.

Bob was sponsored for a total of £63 per 100 points.

Eve was sponsored for a total of £56 per 100 points.

Nan was sponsored for a total of £72 per 100 points.

Pip was sponsored for a total of £54 per 100 points.

Viv was sponsored for a total of £68 per 100 points.

During the 6-hour marathon:

Pip scored 2,835 points.

Eve scored 2,782 points.

Bob scored 2,407 points.

Viv scored 2,293 points.

Nan scored 2,169 points.

38. Remarkably, four of them raised exactly the same amount. Who raised a different amount to the other four?
1
0

## Explanation

Watch out, the scored for each person are not given in the same order as the money sponsored for each person per 100 points. Complete 100 points scored for each person: P=2800, E=2700, B=2400, V=2200, N=2100. Calculations: P=54×28=1512, E=56×27=1512, B=63×24=1512, V=22×68=1496, N=21×72=1512. Viv raised a different amount.

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Five friends wanted to go on holiday together, but they found it difficult to decide where to go. Jo and Mel both wanted to go to Portugal, with France as their second choice. Kim wanted to go to Majorca, while Lexy’s first choice was Greece and Naz’s was Tenerife. Naz and Kim both put France as their second choice, while Lexy gave it as her third choice, preferring Tenerife as her second choice. Kim and Mel put Tenerife as their third choice. Jo’s third choice was Greece, and Naz’s was Majorca.

They agreed to allocate three points for a 1st choice, two points for a 2nd choice and one point for a 3rd choice. The friends decided that they would not go anywhere which was not someone’s first choice.

25. Where did they go on holiday?
0
0

## Explanation

The fastest way to approach this question is to create a table and jot down each persons 1st 2nd and 3rd choices as you read the text as this saves you from constantly having to scan through the text to calculate the points allocated to each place. Once we have the table, we can clearly see that France doesn’t end up as any individual’s first choice, so we can rule out A. For the other locations we can calculate the points allocated: Portugal = 3+3=6; Majorca = 3+1=4; Greece = 3+1=4; Tenerife = 3+2+1+1=7. Therefore, as Tenerife ends up with the largest number of points, the answer is E.

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In March, 20 people voted for the position of chair of a committee. There were three potential candidates: Andrew, James and Roger.

In April, 11 of these people changed their votes, as follows:

3 people changed their vote from Andrew to James
2 people changed their vote from James to Roger
5 people changed their vote from Andrew to Roger
1 person changed their vote from Roger to James

32. Which one of these bar charts could not show the number of votes for the three candidates in March and April?
0
0

## Explanation

For this question, we can’t work out the absolute numbers of votes in March or April, but given the data provided, we can calculate the differences for each candidate. For Andrew we can see that 3 change their vote from him to James and 5 to Roger so overall he loses 8 voters. Quickly scanning through the charts shows that all of them show a decrease of 8. So moving on to the next candidate – we can see than James received 3+1 = 4 more votes than before, but loses 2 to Roger, so overall there’s a difference of 2 votes. Quickly scanning through the answer options shows that there’s only an increase of 1 in answer C, so that is the correct answer as it’s the only chart that cannot be showing the correct number of votes.

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## Instructions

Below is a summary of your answers. You can review your questions in three (3) different ways.

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2. Review questions that are incomplete.
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## Instructions

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## Official TSA Ordered Questions (2008-2019) Section

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