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Official TSA Pin Code Questions (2008-2019)
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Official TSA Pin Code Questions (2008-2019)
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Speed as well as accuracy is important in this section. Work quickly, or you might not finish the paper. There are no penalties for incorrect responses, only marks for correct answers, so you should attempt all questions. Each question is worth one mark.
Calculators are NOT permitted.
Here you will find all TSA Pin Code questions that have been written 2008-2019.
I have so many four digit code numbers to remember that I cannot keep them all in my The banks say you should not write down your Personal Identification Numbers (PINs) for cash and credit cards and keep them in a wallet with the cards. So I can find out what the numbers are, I have devised a code which should be complicated enough to confuse any thief who steals my wallet. I code all the numbers using 1=A, 2=B up to 9=I, 0=J. Then I write the coded numbers down backwards so 1234 is written DCBA. Finally at the end of each coded number I add an extra letter between A and J to say what that particular code is of: C is for credit card; F is for phone card; B is for bicycle lock combination; E is for my Eastern Bank card and D is for my Denton Building Society card.
My list looks as follows:
A |
D | G | E | F |
C | J | D | B |
E |
B |
G | F | A | C |
G | J | A | C |
D |
D |
F | G | C |
B |
Explanation
The correct answer is E.
We need to work backwards, starting with the final step used to make the code. Because at the end of each coded number he adds an extra letter, and ‘B’ is for bicycle, the 5th code in the list is for bicycle as it ends in ‘B’. We then need to write the remaining for letters of the code in the reverse order, so ‘DFGC’ would become ‘CGFD’. We then need to find the number each letter represents by finding their positions in the alphabet: C=3, G=7, F=6, D=4. So the code would be 3764, which is answer E.
To take part in the National Lottery, entrants must select six different numbers between 1 and 49 inclusive.
My mother asked me to buy a National Lottery ticket for her. “Choose any six numbers you like,” she said, “but make sure that each one is a multiple of 3, or contains a 3, or 6 or 9.”
Explanation
The correct answer is E.
49/3=16.3, therefore there are 16 multiples of 3 out of the numbers 1-49. In each group of ten, there will be one each of 3, 6 and 9 as the final digit of the number (ie for 3 there is 3, 13, 23, 33 and 43). However, because 3, 6, 9, 33, 36 and 39 are also multiples of 3, we do not need to count these again, leaving us with 3×3=9 more numbers to chose from. Each number in the 30-39 also has at least one 3 in it, but since we have already counted 30, 33, 36 and 39, the 30s give us 6 additional numbers. Altogether we can choose from: 16+9+6=31 numbers.
All the telephone numbers in my village have six digits and begin with 58. I have accidentally torn up and thrown away a piece of paper on which I had written the telephone number of a friend who lives nearby. The only piece I can find is the scrap shown below:
Explanation
The correct answer is D.
Possible combinations: 588011 (adding the scrap to the initial 58), 581108 (doing the same again but first the scrap is rotated 180 degrees – it gives the same digits but in the reverse order). The ‘8’ on the scrap of paper could be included in the starting ’58’, which would give: 58011_. The final digit here could be any of ten digits 0-9, giving 10 possible combinations starting with 58011. Therefore, the total number of combinations is 1+1+10=12.
I have bought a combination lock for my bicycle. The combination is a three-digit number in the range 000-999 and it is currently set to the manufacturer’s default combination of 999. Before I use the lock I need to set the I want to use a combination where all three digits are different.
Explanation
The correct answer is B.
There are 10 different digits form 0 to 9. So for the first of the 3 digits in the code, you have 10 options. For the second digit, you have 9 options because you have already used one of the 10 original options. For the third digit you therefore have 8 options because you want the digit to be different to the previous 2. Therefore the calculation is 10x9x8=720.
In the main draw of a lottery, six of the balls (which are numbered from 1 to 49) are selected at random, then the numbers chosen are rearranged and displayed in ascending numerical order.
For instance: 3 17 20 29 34 45
In one draw recently, I noticed that the six numbers were made up of a total of ten digits, all different. The lowest number on this occasion was 1 and the highest number was 49, so the range of the six numbers was 48, the greatest possible range for the lottery main draw.
Explanation
The correct answer is E.
To get to 10 digits with only 6 draws you can draw a maximum of 2 single digit numbers. All our digits need to be different. For a small range we need a large “smallest number” and the smallest “largest number”. The largest single digit is “9” but since we need two single digits we need 8 and 9. This leaves us with 4 double digits and 8 numbers for them all to be distinct we need to have a number in 10s, 20s, 30s, 40s. So we used the numbers: 1,2,3,4,8,9 and we are left with: 0,5,6,7. The smallest “largest number we can make is 40. 40 – 8 = 32. The correct answer is E.

Sun, 23 Oct 2022 10:27:51
You can’t get any number in 10s because 1 is already the smallest number: the digit ‘1’ is used.

Wed, 26 Oct 2022 16:07:50
9, 18, 27, 35, 36, 40 ?...
Official TSA Pin Code Questions (2008-2019) Review Screen
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Official TSA Pin Code Questions (2008-2019) Section
Final Answer Review Screen
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Official TSA Pin Code Questions (2008-2019) Section
TI-108
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Sun, 01 Oct 2023 10:09:48
Letters written in 5th code is wrong? Like DFGC are not in the 5th code!